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Don't call "note_interrupt()" with irq descriptor lock held

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This reverts commit f72fa707604c015a6625e80f269506032d5430dc, and solves
the problem that it tried to fix by simply making "__do_IRQ()" call the
note_interrupt() function without the lock held, the way everybody else
does.

It should be noted that all interrupt handling code must never allow the
descriptor actors to be entered "recursively" (that's why we do all the
magic IRQ_PENDING stuff in the first place), so there actually is
exclusion at that much higher level, even in the absense of locking.

Acked-by: Vivek Goyal <vgoyal@in.ibm.com>
Acked-by:Pavel Emelianov <xemul@openvz.org>
Cc: Andrew Morton <akpm@osdl.org>
Cc: Ingo Molnar <mingo@redhat.com>
Cc: Adrian Bunk <bunk@stusta.de>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
This commit is contained in:
Linus Torvalds 2006-11-22 09:32:06 -08:00
parent 0f9005a6f7
commit b42172fc7b
2 changed files with 3 additions and 7 deletions
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4
kernel/irq/handle.c
View File

@ -231,10 +231,10 @@ fastcall unsigned int __do_IRQ(unsigned int irq)
spin_unlock(&desc->lock);
action_ret = handle_IRQ_event(irq, action);
spin_lock(&desc->lock);
if (!noirqdebug)
note_interrupt(irq, desc, action_ret);
spin_lock(&desc->lock);
if (likely(!(desc->status & IRQ_PENDING)))
break;
desc->status &= ~IRQ_PENDING;

6
kernel/irq/spurious.c
View File

@ -147,11 +147,7 @@ void note_interrupt(unsigned int irq, struct irq_desc *desc,
if (unlikely(irqfixup)) {
/* Don't punish working computers */
if ((irqfixup == 2 && irq == 0) || action_ret == IRQ_NONE) {
int ok;
spin_unlock(&desc->lock);
ok = misrouted_irq(irq);
spin_lock(&desc->lock);
int ok = misrouted_irq(irq);
if (action_ret == IRQ_NONE)
desc->irqs_unhandled -= ok;
}