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opt always equals np->opts, so it is meaningless to define opt, and check if opt does not equal np->opts and then try to free opt. Signed-off-by: RongQing.Li <roy.qing.li@gmail.com> Acked-by: Eric Dumazet <edumazet@google.com> Signed-off-by: David S. Miller <davem@davemloft.net>